Q:

Given the function f(x) = βˆ’3^2 + 4x + 6, find f(2) and f(3). Choose the statement that is true concerning these two values.A.) The value of f(2) is the same as the value of f(3).B.) The value of f(2) cannot be compared to the value of f(3).C.) The value of f(2) is smaller than the value of f(3).D.) The value of f(2) is larger than the value of f(3).

Accepted Solution

A:
Answer:D (assuming f(x)=-3x^2+4x+6)Step-by-step explanation:Let's find f(2) and f(3).I'm going to make the assumption you meant f(x)=-3x^2+4x+6 (please correct if this is not the function you had).f(2) means replace x with 2.f(2)=-3(2)^2+4(2)+6Use pemdas to simplify: Β -3(4)+4(2)+6=-12+8+6=-4+6=2.So f(2)=2f(3) means replace x with 3.f(3)=-3(3)^2+4(3)+6Use pemdas to simplify: Β -3(9)+4(3)+6=-27+12+6=-15+6=-9So f(3)=-9-9 is smaller than 2 is the same as saying f(3) is smaller than f(2) or that f(2) is bigger than f(3).