PLZ HELP QUICK!!!!!!..... Figure ABCD has vertices A(−4, 1), B(2, 1), C(2, −5), and D(−4, −3). What is the area of Figure ABCD? (1 point) 24 square units 30 square units 36 square units 45 square units
Accepted Solution
A:
Answer:The area = 30 units²Step-by-step explanation:∵ A (-4 , 1) and (2 , 1)∴ AB is a horizontal segment (same y-coordinates)∴ AB = 2 - -4 = 6 units∵ B (2 , 1) and C (2 , -5)∴ BC is a vertical segment (same x-coordinates)∴ AB ⊥ BC∴ BC = 1 - -5 = 6 units∵ A (-4 , 1) and D (-4 , -3)∴ AD is a vertical segment∴ AD ⊥ AB∴ AD // BC∴ AD = 1 - -3 = 4 units∴ ABCD is trapezium with parallel bases AD , BC and height AB ∵ [tex]A=\frac{b_{1}+b_{2}}{2}h[/tex]∴ [tex]A=\frac{4+6}{2}(6)=30[/tex] units²