Solving and graphing systems of equations-4x + 3y = 3y= 2x + 1How do I solve this and what is the answer, please help me asap!!

Hey Jackson!

-4x + 3y = 3
y = 2x + 1

Ok so what we need to do is solving y= 2x + 1 for y.

So let's start by using the substitution method :)

Substitute 2x + 1 for y in -4x + 3y = 3

-4x+ 3y = 3

-4x + 3(2x + 1) = 3

-4x + (3)(2x) + (3)(1) = 3

-4x + 6x + 3 = 3

2x + 3 = 3

Subtract 3 on both sides

2x + 3 - 3 = 3 - 3

2x = 0

x = 0/2

x = 0

So now since we find the number for x, we gonna use it to help us find the value for y.

To find y, we need to substitute 0 for x in y = 2x + 1

y = 2x + 1

y = 2(0) + 1

y = 0 + 1

y = 1

Thus,

The answer is: y = 1 and x = 0

How to graph?

You need to go on the thing where they put the numbers. y is located on top which has the positive numbers. So when you get there, make a line that comes from the top right side all the way to the bottom left sides. Remember that y = 1 so the line must pass through 1

I am not good with explanation. So I'll leave the graph down below then you'll see what I am talking about :)

Let me know if you have any questions. As always, it is my pleasure to help students like you!